Sunday, April 19, 2009

Straight Line Grapshs

Where does the line cut the x and y axis?

1. y = 5x - 8

2. 4y = 16x + 64

3. 6x = 12 - y

4. y² = 144 + 16x²

5. y + 3x = 18
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10 comments:

  1. shottaApril 25, 2009 at 4:05 PM

    when a line cuts the y-axis the value of x is 0
    therefore:
    y = 5x - 8
    y intercept is 8
    and the x-intercept is 0

    ReplyDelete
  2. shottaApril 25, 2009 at 4:11 PM

    solution 2
    4y = 16x + 64
    to get this equation in the format of the equation of a straight line(y = mx + c)
    divide the whole equation by 4
    therefore
    (4y = 16x + 64)/4
    y = 4x + 16
    once in this format we can then find the y intercept
    y intercept = 16
    x intercept = 0

    ReplyDelete
  3. shottaApril 25, 2009 at 4:16 PM

    solution 2
    6x = 12 - y
    transpose the formula and make it into the format of y = mx + c
    y = 6x - i2
    y intercept = -12
    x intercept = 0

    ReplyDelete
  4. shottaApril 25, 2009 at 4:23 PM

    gettin trouble with the forth one can anyone help me... miss can u check my answers and see if they are correct and notify me before exams.......please.....put up some curved line graphs to solve...i does be on the blog every day

    ReplyDelete
  5. WeezyApril 26, 2009 at 5:06 PM

    shotta
    This should help u

    4. y^2 = 144 + 16x^2
    y = square root of 144 & 16x^2
    so
    y = 4x + 12

    ReplyDelete
  6. starMay 1, 2009 at 12:44 PM

    1) in y=mx+c
    c is = to y
    so 8 is y intercept
    and 0 is x intercept

    ReplyDelete
  7. starMay 1, 2009 at 12:48 PM

    3) put in the form y=mx+c
    y=12-6x
    y=-6x+12
    y intercept is 12

    ReplyDelete
  8. starMay 1, 2009 at 12:49 PM

    4) having problems with
    number 4

    ReplyDelete
  9. starMay 1, 2009 at 12:50 PM

    5)y+3x=18
    y=-3x+18

    y intercept is 18

    ReplyDelete
  10. starMay 1, 2009 at 12:51 PM

    miss i having problems finding the x intercept

    ReplyDelete

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