2) the sum of all the terms from the 5th to the 11th terms (both inclusive)
Anwser
Find the number of terms n from S = n/2(a + l)
- From the first line first term a = -11
- and last term l = 179
- Sum = n/2 (a + l)
- 1680 = n/2 (-11 + 179)
- 1680 = n/2 (168)
- 1680 = 84 n
- n = 1680/84
- n= 20
the sum of all the terms from the 5th to the 11th terms (both inclusive)
Sum of first 11 terms - sum of first 4 terms remember a =-11
Need to get the common difference d
last term 179 is really the 20th term so
20th term = a + (20 - 1) d = 179
-11 + 19d = 179
19d = 190
d = 10
Now you know a = -11 and d = 10
- sum up to 10 terms means n = 10
- sum up to 4 terms means n = 4
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