Recall what is a term. A term is separated by + or - or =
A term consists of parts.
A book is on ething and consist of parts, toc, chapters, cover, pages, etc
Similarily, a term consists of parts, eg
2 + 3mn + 6twb -12 def + 1/2 mb = 120
This equation consists of 6 terms
- 2 is a number term and is a 1 part
- 3mn is a mn term and consists of 3 parts, a number, a m and a n
- 6twb is a twb term and consists of 4 terms, a number, a t, a w and a b
- 12def is a def term and consists of 4 parts, a number, a d, a e and a f
- 1/2 mb is a mb term and consists of 3 parts, anumber, a m and a b
- 120 is a number and is a 1 part
Identify how many terms are present in the equation, what are the trem, and what are the parts.
- 12 mn + 3mds
- 2m^2 + m
- 6mn - 3mpd + 2 m^2
- 20 m^2 - m
- 6mnt - 3mn
For each of the above look for any common part in all the term.
This will go outside the bracket ( ) and inside the bracket put what reamins in each term
12 mn is a mn term and consist of three parts, a number, a m and a n
ReplyDelete3 mds is a mds term and consists of four parts a number a m , a d and a s.
6mnt - 3mn
ReplyDelete6mnt is a term and consists of four parts a number , a m , a n and a t.
3mn is a term and consists of three parts a number a m and a n.
12 mn + 3mds
ReplyDeletecommon term is m
3m ( 4n + ds)
6mnt - 3mn
ReplyDeletethe common terms are m and n
mn ( 6t - 3)
2m^2 + m
ReplyDeletem is the common term
m ( 2 m + 1)
12mn is the term in this case
ReplyDelete12mn consist of three parts; number,m,and n
3mds is the term in this case
3mds cosists of four parts;number,m,d and s
2) 2m^2+m
ReplyDeletem is common in the first term and 2nd term
Pull out m
Therefore m(2m+1)
3)6mn-3mpd+2m^2
ReplyDeleteI first rearrange the equation
2m^2+6mn-3mpd
m is common in all the terms so i pull it
out of the brackets.
therefore i get; m(2m+6n-3pd)
20m^2-m
ReplyDeletem is common in this case
therefore m(20^2-1)
note that m divided in m=1
m is in the first and second term
it was pulled out
5) 6mnt-3mn
ReplyDeletemn are the common terms
3 is a factor of 6
therefore 3mn will be pulled out
3mn(2t-1)
6mnt consist of four parts;a number,m,n,t
-3mn consist of 3 parts;a number,m,n.
12 mn + 3mds
ReplyDeletethe commonn term is 3m since m is common in both terms and 3 is a factor of 12.
ans.= 3m(4n + ds)
2m^2 + m
ReplyDeletethe common trem is m.
ans.= m(2m + 1)
6mn - 3mpd + 2 m^2
ReplyDeletethe common term is m.
ans.= m(6n -3pd + 2m)
20 m^2 - m
ReplyDeletethe common term is m.
ans.= m(20m - 1)
6mnt - 3mn
ReplyDeletethe common term is 3mn.
ans.=3mn(2t - 1)
1)12 mn + 3mds
ReplyDelete12mn is a mn term and consist of three parts, number, m and n
3mds is a mds term and consists of four parts number, m, d, and s.
3m is a factor of both terms and therefore will be placed outside the bracket.
sol: 3m ( 4n + ds)
2)2m^2 + m
ReplyDelete2m^2 is a m^2 term and consists of two parts number, m^2
m is a m term consisting of one part, m.
m is a factor of both terms and therefore will be placed outside the
bracket.
sol: m(2m + 1)
3)6mn - 3mpd + 2 m^2
ReplyDelete6mn is a mn term consting of 3parts number, m, n.
3mpd is a mpd term consisting of four parts number, m, p, d.
2 m^2 is a m^2 term consisting of 2parts, number, m^2
m is a factor of three terms and therefore will be placed outside the
bracket.
sol: m(6n -3pd + 2m)
4)2m^2 - m
ReplyDelete2m^2 is a m^2 term and consists of two parts number, m^2
m is a m term consisting of one part, m.
m is a factor of both terms and therefore will be placed outside the
bracket.
sol: m(2m - 1)
5)6mnt - 3mn
ReplyDelete6mnt is a mnt term consisting of four parts number, m,n,t
3mn is a mn term consisting of three parts number m,n
3mn is a factor of three terms and therefore will be placed outside the
bracket.
sol: 3mn(2t - 1)
My question and answer!!
ReplyDeleteWhat is the expansion of (x+2)^4
ANSWER
ReplyDeleteThis problem is straightforward if you take it step by step.
First, (x + 2)^4 = (x + 2) (x + 2) (x + 2) (x + 2)
Step 1 is to begin with (x + 2) (x + 2). To do this, you multiply each of the elements from the first parenthesis times each of the items in the second. So, you get:
x * x = x^2
x * 2 = 2x
2 * x = 2x
2 * 2 = 4
Add these together, and you get x^2 + 4x + 4
Step 2 is to multiply all that first by x:
x^3 + 4x^2 + 4x
and then by 2:
2x^2 + 8x + 8.
Add them all together and you get: x^3 + 6 x^2 + 12x + 8.
Step 3 is to multiply all that by the last (x + 2).
First by x: x^4 + 6x^3 + 12x^2 + 8x
then by 2: 2x^3 + 12 x^2 + 24x +16
Add those two together and simplify for the final answer:
x^4 + 8x^3 + 24x^2 + 32x +16
6mn - 3mpd + 2 m^2
ReplyDelete6mn is a mn term and consists of three parts a number 6 a m and a n.
3mpd is a mpd term and consists of a number 3 a m, a p and a d
2mn^2
2 m n ^2 is a mn^2 term and consists of a m and a n^2
12mn+3mds
ReplyDeletewell in the first part of the question 12mn there are three parts.......
these are a number, m and n
in the second part 3mds it consist of four parts these are a number,m , d and s
therefore when expanded= 3m(4n+ds)
2. 2m^2 + m
ReplyDeletein the first part of the equation 2m^2
it consist of two parts a number and m
in the second they is only one part which is m
*note ...when solving an equation you should extract like terms
eqn'2m^2+m
solution.... m(2m+1)
3. 6mn - 3mpd + 2 m^2
ReplyDelete6mn consist of three parts a number,
m and n.
3mpd consist of four parts a number,
m, p, and d.
2m^2 consist of two parts a number and m^2
when this equation is worked
you first extact the like terms which is "m" this helps you to get your solution easily...
sol.. 6mn - 3mpd + 2 m^2
= m(6n-3pd+2m)