Friday, March 20, 2009

Log set 3

  1. Solve log[7](x^2) = log[7](2x – 1).
  2. Solve 2log[3](x) = log[3](4) + log[3](x – 1)
  3. Solve log2(x) + log2(x – 2) = 3
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1 comment:

  1. WeezyMarch 20, 2009 at 8:26 PM

    log rules..

    2^3 = 8 <=> log[2]8 = 3

    log[2]ab=log[2]a + log[2] b

    log[2] b/a = log[2] b - log[2] b

    log[2]^b = b log[2]^a

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